Identify all users assigned a PHP version

bloatedstoat

• June 10, 2019 19:50

Hello, We use the CloudLinux PHP selector to assign a PHP version. Is it possible, without having to plough through each username individually, all users currently assigned PHP v5.6 for example? I can see how this is done on a per account basis but I am seeking a list of all users assigned a PHP version. It's really time consuming doing this per account and I am inherently lazy so looking for the path of least resistance. Command line preferably. Thanks.

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  Infopro

  • June 11, 2019 09:38

  This thread may be helpful:

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  bloatedstoat

  • June 11, 2019 10:10

  @Infopro I read that article too before chipping in here. Bar anyone else piping up on this you've pretty much confirmed to me that there is no native method. Thanks mate.

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  cPanelLauren

  • June 11, 2019 18:22

  There isn't a native way but that command they provide in there will get that done for you.

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  Infopro

  • June 11, 2019 18:30

  We use the CloudLinux PHP selector to assign a PHP version.

  
  MultiPHP Manager in WebHost Manager makes doing what you seek, rather trivial. I assume you already know this.

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  bloatedstoat

  • June 11, 2019 20:23

  @Infopro In my case every domain displays PHP5.6 in MultiPHP Manager in WHM. The versions actually deployed are mostly version 7 by way of the CloudLinux PHP Selector chosen in cPanel. I've never used MultiPHP Manager in WHM. @cPanelLauren thanks, it does in a fashion. My knowledge of command line voodoo is limited, ideally I'd like a command that displays all users of a "chosen" version listed next to just the username. The output from the one on the CL forum is overly verbose and cluttered - especially when dealing with lots of accounts. I'm sure there's a way to do this ... he said whilst throwing down the gauntlet ....

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  cPanelLauren

  • June 12, 2019 14:50

  Hi @bloatedstoat How about this? for user in /var/cpanel/users/*;do if [[ ! "${user##*/}" = system ]]; then php="$(selectorctl -c -u "${user##*/}" 2>&1)";echo "${user##*/} ${php%%$'\t'*}";fi;done
  I can't take all the credit for this though, one of my coworkers is a genius with one-liners like this.

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  bloatedstoat

  • June 13, 2019 23:45

  Thanks @cPanelLauren and thanks to the genius in the cPanel colony. Appreciated.

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  SS-Maddy

  • June 20, 2019 17:37

  Hi @bloatedstoat How about this? for user in /var/cpanel/users/*;do if [[ ! "${user##*/}" = system ]]; then php="$(selectorctl -c -u "${user##*/}" 2>&1)";echo "${user##*/} ${php%%$'\t'*}";fi;done
  I can't take all the credit for this though, one of my coworkers is a genius with one-liners like this.

  
  Loved this. Tweeted too :)

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  Bob Gordon

  • June 20, 2019 18:56

  selectorctl --list-users --version=5.6
  will show all users on PHP version you specify!

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  jonathan.mann

  • November 04, 2021 16:32

  I'm in a similar situation as the OP. I'm working with CentOS servers. Is there a version of selectorctl that I can use for say, CentOS 6?

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  cPanelAnthony

  • November 04, 2021 18:13

  Hello! As long as you're using EasyApache 4, you should be able to utilize "MultiPHP Manager" in WHM.

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  jonathan.mann

  • November 04, 2021 18:47

  Hello! As long as you're using EasyApache 4, you should be able to utilize "MultiPHP Manager" in WHM. whmapi1 php_get_vhost_versions | egrep 'account:|version:|vhost:' | sed 's/vhost/domain/'
  Can I include some kind of modifier in this to only list active accounts/domains?

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