[Resolved] Use api 2 call to get user information and convert it to php variable

davidhogan

• March 10, 2014 10:16

Hi, I'm currently trying to get user information via whm's xmlapi php class and convert the information into php variables. My code looks like this [PHP] //Ive deleted any information that could be used to login to my server $server_username ='root'; $ip = '0.0.0.0'; $root_hash = 'hash goes here'; //server ip is passed $xmlapi = new xmlapi($ip); //server username normally root and hash is passed $xmlapi->hash_auth($server_username,$root_hash); $whm_username = 'some_user'; $xmlapi->set_debug(1); $args = array('display' => 'bandwidthusage'); $xmlapi->api2_query($whm_username, 'StatsBar', 'stat', $args); [/PHP] thank you in advance for your assistance and suggestions David

• 

  vanessa

  • March 11, 2014 03:28

  Just set the result to a variable: hash_auth($server_username, $root_hash); $xmlapi->set_debug(0); $args = array('display' => 'bandwidthusage'); $result = $xmlapi->api2_query($cpanel_username, 'StatsBar', 'stat', $args); print_r($result);
  This will return: [SimpleXMLElement Object ( [apiversion] => 2 [data] => SimpleXMLElement Object ( [name] => bandwidthusage [_count] => 8.97 [_max] => unlimited [_maxed] => 0 [count] => 8.97 [feature] => bandwidth [id] => bandwidthusage [item] => Monthly Bandwidth Transfer [langkey] => INDXBandwidth [max] => unlimited [module] => Stats [normalized] => 1 [percent] => 0 [percent10] => 0 [percent20] => 0 [percent5] => 0 [units] => MB [zeroisunlimited] => 1 ) [event] => SimpleXMLElement Object ( [result] => 1 ) [func] => stat [module] => StatsBar )
  Then all you have to do is pull out the variables you want. For example, to get the value of _max in the above result: $max = $result->data->_max;
  Will return: unlimited
  Hope this helps.

  0
• 

  cPanelMichael

  • March 12, 2014 15:56

  Hello :) The previous post seems to accurately answer your question so I am marking this thread as resolved. Feel free to update this thread if you have any additional questions. Thank you.

  0

Please sign in to leave a comment.